17x^2+19x=1848

Solution for 17x^2+19x=1848 equation:

17x^2+19x=1848

We move all terms to the left:

17x^2+19x-(1848)=0

a = 17; b = 19; c = -1848;
Δ = b2-4ac
Δ = 192-4·17·(-1848)
Δ = 126025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{126025}=355$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-355}{2*17}=\frac{-374}{34}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+355}{2*17}=\frac{336}{34}
=9+15/17
$